1 2 3 3 5 2 3 5 3 1 4 1
f ( 1 3 ) = 3 − 1 3 − 1 −−−−−√ = 3 − 1 2 −−√
f ( 1 3 ) = 3 − 1 3 − 1 −−−−−√ = 3 − 1 2 −−√
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